x^2+56x-380=0

Solution for x^2+56x-380=0 equation:

x^2+56x-380=0

a = 1; b = 56; c = -380;
Δ = b2-4ac
Δ = 562-4·1·(-380)
Δ = 4656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4656}=\sqrt{16*291}=\sqrt{16}*\sqrt{291}=4\sqrt{291}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{291}}{2*1}=\frac{-56-4\sqrt{291}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{291}}{2*1}=\frac{-56+4\sqrt{291}}{2}
$